CSIR UGC NET Exam Pattern, Syllabus, Exam Date, Eligibility: UGC NET By CSIR is to be conducted twice in a year, in the month of June | December. Which is make possible via Online Registration and its application form on the official website of CSIR i.e. ugcnetonline.in.  If an individual are going to appear in this examination we must recommended to check the CSIR UGC NET Exam Pattern and its Syllabus of all Subjects, that will be help you to crack the exam. In this article, we have mentioned the UCG NET Exam Pattern, links which is relate to its Application form, admit Card, How to Apply, Cutoff, Result etc.

CSIR UGC NET Exam Pattern

  • The Exam will be direct in a sum of five subjects/topics which is, Mathematical Sciences, Life Sciences, Earth, Atmospheric, Physical Sciences Chemical Sciences, Ocean and Planetary Sciences.
  • It includes of a particular MCQ paper having 200 marks.

The CSIR UGC NET question paper will be break into 3 Parts-A, B, & C as elaborate below:

  • Part A – In the first part has common to all the topics/subjects and will consist questions pertaining to graphical analysis, logical reasoning, Numerical ability and General Aptitude etc.
  • Part B – In this part of the exam will consists conventional MCQs covering different topics of the relevant subject. For subject of the Engineering Sciences, though, questions relating to Mathematics and Engineering Aptitude will be consisted.
  • Part C – This is the last section/part that will includes of questions of a greater/higher value that would be prepared/designed to test a student’s knowledge about a scientific concepts/topics and/or its application. Questions in this part would be of an analytical in nature. Engineering Sciences will include Multiple Choice Questions as subject-related.

Negative Marking: There shall be a negative marking for the incorrect answers according to the subject wise scheme of the exam. The advantage of the marks shall be provided to only those applicants who are attempt the question in condition, any question will be found to be incorrect at the after stage formerly.

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